Question

One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of 44 u. The alkene is
A. ethene
B. propene
C. 1-butene
D. 2-butene

Answer 1

Correct Answer - D
The aldehyde with molecular mass 44 u is `CH_3CHO` (acetaldehyde). Therefore, the symmetrical alkene is 2-butene
`underset"2-Butene"(CH_3CH=CHCH_3)underset((ii)Zn//H_2O)overset((i)O_3//CH_2Cl_2, 196K)to underset"(Mol. mass =44 u)"underset"Acetaldehyde"(2CH_3CHO)`