Correct Answer - 1.067 kJ
From the expression of heat (q),
`q=m.c.DeltaT`
Wher,
c= molar heat capacity
m= mass of substance
`DeltaT` = change in temperature
Substituting the values in the expression of q:
`q=((60)/(27)"mol")(24 J "mol"^(-1)K^(-1))(20 K)`
q=1066.7J
q=1.07 kJ