Question

Calculate the number of `KJ` necessary to raise the temperature of `60.0 gm` of aluminium from `35^(@)` to `55^(@)C`. Molar heat capcacity of `Al` is `24 J mol^(-1)K^(-1)`

Answer 1

`q = nC Delta T = ((60)/(27)) xx 24 xx (55-35) = 1066 J = 1.066 kJ`