The equilibrium constant for a reaction is `10`. What will be the value of `DeltaG^(Θ)`? `R=8.314 J K^(-1) mol^(-1), T=300 K`.

From the expression,
`DeltaG^(theta)=-2.303RT "log"K_(eq)`
`DeltaG^(theta)` for the reaction,
`=(2.303)(8.314 JK^(-1)"mol"^(-1)) (300K)` log10
`-5744.14 J"mol"^(-1)`
`-5.744 kJ "mol"^(-1)`

The equilibrium constant for a reaction is `10`. What will be the value of `DeltaG^(Θ)`? `R=8.314 J K^(-1) mol^(-1), T=300 K`.

Please log in or register to add a comment.

1 Answer

Please log in or register to add a comment.

Find MCQs & Mock Test

Related questions

Categories