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The equilibrium constant for a reaction is `10`. What will be the value of `DeltaG^(Θ)`? `R=8.314 J K^(-1) mol^(-1), T=300 K`.

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The equilibrium constant for a reaction is `10`. What will be the value of `DeltaG^(Θ)`? `R=8.314 J K^(-1) mol^(-1), T=300 K`.
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`DeltaG^(Θ) =-2.303RT log K`
`=-2.303xx8.314 J K^(-1) mol^(-1)xx300 Kxxlog 10`
`=-5744.1 J`
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