Data : \(\lambda _{L\infty}\) = 912 Å
For hydrogen spectrum, \(\cfrac{1}{\lambda}\) = RH\((\cfrac{1}{n^2}-\cfrac{1}{m^2})\)

as n = 5 and m = ∞
From Eqs. (1) and (2), we get,
\(\cfrac{\lambda_{ pa\infty}}{\lambda_{L\infty}}\) = \(\cfrac{R_H} {R_H/9}\) = 9
∴ λpa\(_\infty\) = 9 λlL\(_\infty\) = (9) (912) = 8202 Å
\(\cfrac{\lambda_{ pf\infty}}{\lambda_{L\infty}}\) = \(\cfrac{R_H} {R_H/9}\) = 25
∴ λpf\(_\infty\) = 25λL\(_\infty\) = (25) (912) = 22800 Å
This is the series limit of the pfund series.