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Total mass of neutrons in `7 mg` of `.^(14)C` is:

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Total mass of neutrons in `7 mg` of `.^(14)C` is:
A. `3xx10^(20) kg`
B. `4xx10^(-6) kg`
C. `5xx10^(-7) kg`
D. `4xx10^(-7)kg`
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Correct Answer - B
`7 mg C^(14)=7xx10^(-3)`
`14 g C^(14)-=8N "neutron"`
`7xx10^(-3)gC^(14)-=(8Nxx7xx10^(-3))/(14)"neutron"`
`-=(8xx6.023xx10^(23)xx7xx10^(-3)xx1.675xx10^(-27))/(14)kg`
`-=40.35xx10^(-7) kg "neutron"`
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