Question

Chloroethene is treated with sodium amide in liquid ammonia. The major product is
A. acetylene
B. ethenamine
C. sodium ethynide
D. 2-chloroethenamine

Answer 1

Correct Answer - C
`CH_2=CH-Clunderset(NH_3)overset(NaNH_2)toCH-=CHunderset(NH_3)overset(NaNH_2)toCH_3-=overline(C)Na^(+)+NH_3`
Sodamide in liquid ammonia is a strong base. Thus, it causes the dehydrochlorination of chloroethene to give acetylene. Being acidic in nature, it reacts with `NaNH_2` to form sodium acetylide.