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A hydrocarbon (A) reacts with sodium amide and then with ethylbromide to produce another hydrocarbon (B) which on ozonolysis by oxidative method yields propanoic acid only. The hydrocarbons (A) and (B) are, respectively.
A. but-1-yne and hex-3-yne
B. but-1-yne and hex-3-ene
C. propyne and hex-3-yne
D. propyne and pent-2-yne

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Best answer
Correct Answer - A
image
Working backwards we get the answer:
Now we confirm it by performing the reaction:

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