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`CH-=CHoverset(NaNH_(2))to[A]overset(CH_(3)Br)to[B]`

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`CH-=CHoverset(NaNH_(2))to[A]overset(CH_(3)Br)to[B]`
A. `CH_(2)=CH-CH=CH_(2)`
B. `HC-=C-CH_(3)`
C. `CH_(2)=CH-CH_(3)`
D. `CH_(3)-CH_(2)-CH_(3)`
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Correct Answer - B
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