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`H_(3)C-C=Choverset(1.NaNH_(2))underset(2.CH_(3)CH_(2)Br)rarrAoverset(H_(2))underset(Pd-BaSO_(4)B:`

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`H_(3)C-C=Choverset(1.NaNH_(2))underset(2.CH_(3)CH_(2)Br)rarrAoverset(H_(2))underset(Pd-BaSO_(4)B:`
A. A is `H_(3)C-CH_(2)-C-=CH`
B. A is `CH_(3)-C-=C-CH_(2)-CH_(3)`
C. image
D. image
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1 Answer

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Correct Answer - B::C
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`CH-=CHoverset(NaNH_(2))to[A]overset(CH_(3)Br)to[B]`
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