Question

There are three samples of `H_(2)O_(2)` labelled as `10 vol,15 vol,20 vol`. Half liter of each sample are mixed and then diluted with equal volume of water. Calculate the volume strength of resultant solution.

Answer 1

Volume strength =`5.6xx` Normality
Or
`V=5.6xxN`, Total volume =`(1/2+1/2+1/2)+3/2=3L`
`N_(1)=10/5.6,N_(2)=15/5.6,.N_(3)=20/5.6`
`N_(1)V_(1)+N_(2)V_(2)+N_(3)V_(3)=N_(R)V_(R)`
`10/5.6xx1/2+15/5.6xx1/2+20/5.6xx1/2=N_(R)xx3L`
`impliesN_(R)=1.339`
Volume strength `=N_(R)xx5.6`
`=1.339xx5.6=7.5`