Question

0.5L each of three samples of H₂O₂ labelled 10 vol, 15 vol and 20 vol are mixed and then diluted with equal volume of water. What is the strength of resultant H₂O₂ solution?

Answer 1

Volume strength of H₂O₂ solution = 5.6 × Normality

Normality = \(\frac{\textit{Vol. strength}}{5.6}\)

Normality of 10 vol of H₂O₂ = \(\frac{10}{5.6}\)N

Normality of 10 vol of H₂O₂ = \(\frac{15}{5.6}\)N

Normality 20 vol of H₂O₂ = \(\frac{20}{5.6}\)N

Let 500 mL of each solution is mixed and then total volume of mixture becomes = 1500 mL. Since it is diluted with equal volume of water, total volume becomes 3000 mL.

Applying normality equation N₁V₁ + N₂V₂ + N₃V₃ = N₄V₄