Strength of H2O2 = \(\frac{Weight\,of\,H_2O_2}{Volume\,of\,solution(L)}\)
= \(\frac{3.4g\times1000}{448L}\)
= 7.6 g/L
\(\underset{(2\times34g)}{2H_2O_2}\longrightarrow2H_2O+\underset{(22.4L)\,at\,NTP}{O_2}\)
68 g of H2O2 produces 22.4 litres at oxygen gas at NTP.
Therefore,
7.6g of H2O2 will produce
= 22.4/68 x 7.6
= 2.5 litre at oxygen.
Thus, volume strength of given H2O2 solution is 2.5
Hence, option(c) is Right answer.