Question

The compressibility factor (Z) for one mole of a gas is more than one under S.T.P. conditions. Therefore
A. `V gt 11.2 L`
B. `V lt 22.38 L`
C. `V gt 22.38 L`
D. `V = 22.38 L`

Answer 1

Correct Answer - C
`Z = (PV)/(nRT)`, if `Z gt 1`
`(PV)/(nRT) gt 1` or `V gt (nRT)/(P)`
`V gt ((1mol) xx (0.0821 L atmK^(-1) mol^(-1)) xx 273K)/((1atm)) gt 22.4 L`