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2 लीटर के पात्र में 17 ग्राम अमोनियम के सक्रिय द्रव्यमान कि गड़ना करों।

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`NH_(3)` का सक्रिय द्रव्यमान
`=W/(m xx V_(L)) = 17/(17 xx 2)=0.5` मोल `लीटर^(-1)`

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