Question

Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc, Following reaction takes place
`Zn+2HClrarrZnCl_(2)+H_(2)`
Calculate the voluem of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP, atomic mass of Zn=65 .3u

Answer 1

`underset(65.u (65.3g))(Zn(s)+2HCl(aq))overset("S.T.P")(rarr)Zn.Cl_(2)(aq)+underset(22.7L)(H_(2)(g))`
65.3 g of zinc evolve hydrogen gas at S.T.P = 22.7 L
32.65 g of zinc evolve hydrogen gas at S.T.P `= ((32.65g))/((65.3g))xx(22.7L)=11.35L`.