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How much quantity of zinc will have to be reacted with excess of dilute `HCl` solution ti produce sufficient hydrogen gas for completely reacting with

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How much quantity of zinc will have to be reacted with excess of dilute `HCl` solution ti produce sufficient hydrogen gas for completely reacting with the oxygen obtained by decomposing `5.104g` of potassium chlorate?
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Correct Answer - `8.124gZn`
`1.0` mole of `KClO_(3) -= 3.0` mole of `Zn`
`(5.104)/(122.5)` mole `KClO_(3)=(3xx5.104)/(122.5)`
mol of `Zn = (3xx5.104xx65)/(122.5)=8.124 " "g" " Zn`
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