Correct Answer - B
Average reading of student `A=(3.01+2.99)/(2)=3.00`
Average reading of student `B=(3.05+2.95)/(2)=3.00`
Average reading of both the student are the same (3.00) and match the correct value. However, the actual readings by student A are more precise since these are closer to the correct value and the difference between these is only 0.02. On the other, the difference in the readings made by student B is 1.0. The results of the student A are therefore, both precise and accurate.