Average of readings of student, `A=(3.01+2.99)/(2)=300`
Average of readings of student ,B`=(3.05+2.95 )/(2)=300`
Correct reading = 3.00
For both studnets average value is close to the correct value. Hence readings of both are accurate
Readings of student A are close to each other (differ only by 0.02) and also close to the correct reading, of A are precise also. But readings of B are not close to each other (differ by 0.1) and hence are not precise.