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The solubility product of a sparingly soluble salt `AB` at room temperature is `1.21xx10^(-6)`. Its molar solubility is
A. `1.21xx10^(-6)`
B. `1.21xx10^(-3)`
C. `1.1xx10^(-4)`
D. `1.1xx10^(-3)`

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Correct Answer - D
`AB` is a binary electrolyte.
`S=sqrt(K_(sp)=sqrt(1.21xx10^(-6))=1.1xx10^(-3) M`

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