Question

Calcualte the volume occupied by `5.25g` of nitrogen gas under a pressure fo `74.2 cm Hg` and at `26^(@) C`.
A. `7.4I L`
B. `4.67 L`
C. `5.93 L`
D. `6.86 L`

Answer 1

Correct Answer - B
`n = ("Mass")/("Molar mass")` and `n = (PV)/(RT)`
`:.` Volume `= (("Mass")/("Molar mass")) ((RT)/(P))`
`((5.25g)(0.821 "L atm K"^(-1) "mol"^(-1)) (229 K))/((28g "mol"^(-1)) ((74.2)/(76) "atm"))`
`( :. 1 "atm = 76 cm Hg")`
`= 4.67 L`