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How many grams of caustic potash required to completely neutralise `12.6 g HNO_(3)`?

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How many grams of caustic potash required to completely neutralise `12.6 g HNO_(3)`?
A. (a)`22.4 KOH `
B. (b)` 1.01 KOH`
C. (c )` 6.02 KOH`
D. (d)`11.2 KOH `
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Correct Answer - D
`HNO_(3)+KOH rarr KNO_(3)+H_(2)O`
`12.6/63=0.2 "mole", HNO_(3)-= KOH`
`0.2"mole"-= 0.2 "mole"`
`0.2xx56=11.2 g`.
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