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सरल आवर्त गति करते हुए किसी कण का अधिकतम त्वरण `alpha` तथा `beta` अधिकतम वेग है तो इसके कम्पन्न का आवर्तकाल होगा
A. `alpha/beta`
B. `beta^2/alpha`
C. `(2pibeta)/alpha`
D. `beta^2/alpha^2`

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Correct Answer - C
अधिकतम त्वरण= `omega^2a=alpha` , अधिकतम वेग= `omegaa=beta`
`therefore omega=alpha/beta` अथवा `T=(2pi)/omega=(2pibeta)/alpha`

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