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The root mean square velocity of hydrogen molecules at 300 K is `1930 ms^(-1)`. The rms velocity of oxygen molecules at 1200 K will be
A. `1930 m//s`
B. `965 m//s`
C. `3960 m//s`
D. `482.5 m//s`

1 Answer

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Best answer
Correct Answer - B
`((v_(rms))_(O_(2)))/((v_(rms))_(H_(2))) = sqrt(T_(O_(2))/T_(H_(2)) ((M_(0))_(H_(2)))/((M_(0))_(O_(2)))) =sqrt(1200/(300).2/32)=1/2`
`(v_("rms"))_(O_(2))=((v_("rms"))_(H_(2)))/(2)=1930/2=965 m//s`

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