Question

A hydrocarbon (X) was found to have a molecular weight of 80-85. A 10.02 mg sample took up `8.40mL` of `H_(2)` gas measured at `0^(@)C` and 760 mm pressure. Ozonolysis of (X) yields only `HCHO` and `OHC-CHO`. What was hydrocarbon?
A. `C_(6)H_(8)`
B. `C_(6)H_(10)`
C. `C_(6)H_(12)`
D. `C_(6)H_(14)`

Answer 1

Correct Answer - A::B::C
Moles of `H_(2)` taken up
`= (8.40 xx 10^(-3))/(22.4) = 3.75 xx 10^(-4)`
Moles of compound `=(10.02 xx 10^(-3))/(22.4) = 1.254 xx 10^(-4)`
Thus, moles of `H_(2)` taken up by 1 mole of compound `=(3.75 xx 10^(-4))/(1.254 xx 10^(-4)) =3`
Therefore, molecules has three double bonds and it may be hexa-1,3,5-triene.