Correct Answer - A::B::C
Moles of `H_(2)` taken up
`= (8.40 xx 10^(-3))/(22.4) = 3.75 xx 10^(-4)`
Moles of compound `=(10.02 xx 10^(-3))/(22.4) = 1.254 xx 10^(-4)`
Thus, moles of `H_(2)` taken up by 1 mole of compound `=(3.75 xx 10^(-4))/(1.254 xx 10^(-4)) =3`
Therefore, molecules has three double bonds and it may be hexa-1,3,5-triene.