Question

For the equilibrium system `2HX(g) hArr H_(2)(g)+X_(2)(g)` the equilibrium constant is `1.0xx 10^(-5)`. What is the equilibrium concentration of HX if the equilibrium concentrations of `H_(2)` and `X_(2)` are `1.2xx10^(-3) M` and `1.2 xx 10^(-4) M` respectively ?
A. `12 xx 10^(-4) M`
B. `12 xx 10^(-3) M`
C. `12 xx 10^(-2) M`
D. `12 xx 10^(-6) M`

Answer 1

Correct Answer - C
`[HX]^(2)=([H_(2)][X_(2)])/(K_(c))`