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For the reactions
`A hArr B, K_(c ) =1`
`B hArr C, K_(c)=2`
`C hArr D, K_(c)=3`
`K_(c)` for the reaction `A hArr D` is
A. 5
B. 6
C. 15
D. 1

1 Answer

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Best answer
Correct Answer - B
`([B])/([A])=1,([C])/([B])=2,([D])/([C])=3.`
On multiplying the three, we get
`([D])/([A])=1xx2xx3=6`

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