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The density of ice `x cm^(-3)` and that of water is `y gcm^(-3)`. What is the change in volume when `mg` of ice melts?
A. `m(y-x)cm^(3)`
B. `(y-x)/(m) cm^(3)`
C. `mxy(x-y)cm^(3)`
D. `m((1/y-1/x) cm^(3)`.

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Correct Answer - D
Volume of ice = `M/(x)` volume of water = `M/y`
`:. Change in volume =`(M)/(x) - (M)/(y) = M((1)/(y)-(1)/(x)) cm^(3)` .

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