Question

What will be the length of mercury column in a barometer tube, when the atmospheric pressure is 76 cm of mercury and the tube is inclined at an angle of `30 ^(@)` with the horizontal direction ?

Answer 1

Here, h=76 cm `theta=30^(@)`
If l is the length of mercury column is the barometer tube then
`(h)/(l)=sin 30^(@) implies (76cm)/(l)=(1)/(2)`
`implies " " l=2xx76=152 cm`