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A particle is moving along a circular along a circular path of radius 5 m with a uniform speed `5ms^(-1)`. What will be the average acceleration when the particle completes half revolution?
A. Zero
B. `10ms^(-2)`
C. `10pims^(-2)`
D. `(10)/(pi)ms^(-2)`

1 Answer

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Best answer
Correct Answer - D
`a_(av)=(Deltav)/(Deltat)=(2xx5)/(pi)=(10)/(pi)ms^(-2),T=2pi`

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