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A 0.02 cm liquid column balances the excess pressure inside a soap bubbl of radius 7.5 mm. Determine the density of the liquid. Surface tension of soap solutionn `0.03 Nm^-1`.

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The excess pressure inside a soap bubble
`/_P=4S/R=(4xx0.03Nm^-1)/(7.5xx10^-3m)=15Nm^-2`
The pressure due to 0.02 cm of the liquid column ils
`/_P=hrhog`
`=(0.02xx10^-2m)rho(9.8ms^2)`
Thus, `16 Nm^-2=(0.02xx10^-2m)rho(9.8ms^-2)`
`or rho=8.2x10^3kgm^-3`

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