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Find the excess pressure inside a mercury drop of radius 2.0 mm. The surface tension oif mercury `0.464Nm^-1`.

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Find the excess pressure inside a mercury drop of radius 2.0 mm. The surface tension oif mercury `0.464Nm^-1`.
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The excess pressure inside the drop is
P_2-P_1=2S/R`
`=(2xx0.464Nm^-1)/(2.0xx10^-3m)=464Nm^-2`
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