Question

In an organ pipe the distance between the adjacent node is `4 cm`. Find the frequency of source if speed of sound in air is `336 m//s`.

Answer 1

Correct Answer - `4.2 kHz`
`(lambda)/(2) = 4 xx 10^(-2)m , lambda = 8 xx 10^(-2)m`
`n = (V)/(lambda) = (336)/(8 xx 10^(-2)) = 4200 Hz = 4.2 KHz`