Question

A hammer of mass 1 kg moving with speed of `6 ms^(-1)` strikes a wall and comes to rest in 0.1 s . Calculate (i) the impules of force (ii) the retardation of the hammer , and (iii) the retarding force that stops the hammer .

Answer 1

Here , `m = 1 kg , u = 6 m//s , upsilon = 0 , t = 0.1 s `
Impulse `= F xx t = m (upsilon - u ) = 1 (0-6) = - 6 Ns`
Retarding force that stops the hammer ,
` F = (Fxxt)/(t)= (6)/(0.1)=60 N `
Retardation of hammer ,
` a = (F)/m = (60)/1 = 60 m//s^(2) ` .