Question

A hammer of mass 1 kg moving with speed of `6 ms^(-1)` strikes a wall and comes to rest in 0.1 s . Calculate (i) the impules of force (ii) the retardation of the hammer , and (iii) the retarding that stops the hammer .

Answer 1

(i) Impulse =`Fxxt`=m(v-u)=1(0-6)=-6 Ns
(ii) Average retarding force that stops the hammer
`F=("Impulse")/("Time")=(6)/(0.1)`=60 N
(iii) Average retardation, `a=(F)/(m)=(60)/(1)=60ms^(-2)`