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Acceleration of a particle in SHM at displacement `x=10 cm` (from the mean position is `a =-2.5 cm//s^(2)`). Find time period of oscillations.

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Acceleration of a particle in SHM at displacement `x=10 cm` (from the mean position is `a =-2.5 cm//s^(2)`). Find time period of oscillations.
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Correct Answer - A::B::D
Time period is given by
`T = 2pisqrt(|(x)/(a)|)`
Substituting the values we have,
`T = 2pisqrt((10)/(2.5)) = (4pi)s`
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