Here , ` h = 9.8 cm , upsilon ? `
As is clear from
`R cos alpha = (m upsilon)^(2)/(r)`
`R sin alpha = mg`
Dividing , we get , `tan alpha = (rg)/(upsilon^(2))` or `(r)/(h)=(rg)/(upsilon^(2)`
`upsilon sqrt(gh)= sqrt(9.8 xx (9.8)/(100)) = 0.98 m// s ` .