Question

A particle performs SHM on a straight line with time period `T` and amplitude`A`. The average speed of the particle between two successive instants, when potential energy and kinetic energy become same is
A. `(A)/(T)`
B. `(4sqrt(2)A)/(T)`
C. `(2A)/(T)`
D. `(2sqrt(2)A)/(T)`

Answer 1

Correct Answer - B
`(1)/(2)kX^(2) = (1)/(2)k(A^(2) - X^(2))`

`:. X = +- (A)/sqrt(2)`
Average speed `= (d)/(t) = (sqrt(2)A)/(T//8 + T//8)`
` = (4 (sqrt2) A)/(T)` .