Question

An object performs SHM of amplitude 5 cm and time period 4 s. If timing is started when the object is at the centre of the oscillation i.e., x=0 then calculate.
(i) Frequency of oscillation.
(ii) The displacement at 0.5 S.

Answer 1

(i) Frequency, `n=(1)/(T)=(1)/(4)=0.25` Hz
(ii) The displacement equation of object is x=A` "sin "omegat` so t=0.5 s
`x=5"sin "(2pi xx 0.25xx0.5)=5 "sin"(pi)/(4)=(5)/(sqrt(2))` cm