Question

A force of `50N` is inclined to the vertical at an angle of `30^(@)` Find the acceleration it produes in a body of mass `2kg` which moves in the horizontal direction .

Answer 1

Correct Answer - `12.5m//s^(2)`
Here, `F = 50N` angle with verticle `0 = 30^(@)`
In the horizontal direction,
`a = ("horizontal force")/("mass") = (F sin0)/(m) = (50sin30^(@))/(2)`
`=12.5 m//s^(2)` .