Question

A force of 50N acts in the direction as shown in figure. The block of mass 5kg, resting on a smooth horizontal surface. Find out the acceleration of the block.

Answer 1

Free body diagram

where, `F_(x)=`Horizontal component of the force
`F_(y)`= Verticle component of the force
Horizontal component of the force `=50 sin 60^(@)=(50sqrt(3))/(2)`
Acceleration fo the block a
`=("component of force in the direction of acceleration")/("mass")`
`=(50sqrt(3))/(2)xx(1)/(5)=5sqrt(3) ms^(-2)`