Question

A rope of mass `0.5kg` is pulling a block of mass `10kg` under the action of force of `31.5N` If the block is resting on a smooth horizontal surface calculate the force of reaction exerted by the block on the rope .

Answer 1

Correct Answer - `30N` .
Total mass `= m + M = 0.5 + 10 = 10.5 kg`
`F= 31.5 N`
`:.a = (F)/((m + M)) = (31.5)/(10.5) = 3m//s^(2)`
Force of reaction exerted block on the rope
`R = M xx a = 10 xx 3 = 30 N` .