Question

A force of 50N acts in the direction as shown in figure. The block of mass 5kg, resting on a smooth horizontal surface. Find out the acceleration of the block.

Answer 1

Horizontal component of the force `=F sin theta=50sin 60^(@)=(50sqrt(3))/(2)N`
acceleration of the block `a=(F sin theta)/(m)=(50sqrt(3))/(2)xx(1)/(5)=5sqrt(3)m//s^(2)`