Question

For traffic moving at `60km//h` if the radius of the curve is `0.1km` what is the correct angle of banking of the road Given `g = 10m//s^(2)` .

Answer 1

Correct Answer - `15.5^(@)`.
Here, `upsilon = 60 km//h = (60 xx 1000)/(60 xx 60) m//s = (50)/(3) m//s`
`r = 0.1 km = 100 m, theta = ? g = 10m//s^(2)`
`tan theta = (upsilon^(2))/(rg) = (50)/(3) xx (1)/(100 xx 10) = 0.2777`
`theta = tan^(-1) (0.2777) =15.5^(@)` .