Question

For traffic moving at `60km//h` if the radius of the curve is `0.1km` what is the correct angle of banking of the road Given `g = 10m//s^(2)` .

Answer 1

In case of banking `tan theta=(v^(2))/(rg)"Here" v=60km//h=60xx(5)/(18)ms^(-1)=(50)/(3)ms^(-1) r=0.1 "km"=100m`
`"So," tan theta=(50//3xx50//3)/(100xx10)=(5)/(18)Rightarrow theta=tan^(-1)((5)/(18))`