Question

If the equation for the displacement of a particle moving in a circular path is given by `(theta)=2t^(3)+0.5`, where `theta` is in radians and `t` in seconds, then the angular velocity of particle after `2 s` from its start is
A. `8 rad//s`
B. `12 rad//s`
C. `24 rad//s`
D. `36 rad//s`

Answer 1

`theta=2t^(3)+0.5`
`omega=(d theta)/(dt)=6t^(2)`
At `t=2 s, omega=6(2)^(2)=24 rad//s`