A block of mass `m` is placed at rest on a smooth wedge of mass M placed at rest on a smooth horizontal surface. As the system i

Correct Answer - C::D
Out of two blocks, one block of mass `m` is moving in vertical direction also (downwards). Therefore COM is moving vertically downwards and momentum of the system is not conserved in vertical direction.

A block of mass `m` is placed at rest on a smooth wedge of mass M placed at rest on a smooth horizontal surface. As the system is released

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