Question

A particle is thrown with velocity `u` at an angle `prop` from the horizontal. Another particle is thrown with the same velocity at an angle `prop` from the verticle. What will be the ratio of times of flight of two particles ?

Answer 1

For first particles angle of projection from the hortizontal is `prop`.
So `T_1 = (2usinprop)/(g)`
For second particle, angle of projection from the vertical is `prop`. it mean from the horizontal is `(theta - prop)`
`therefore T_(2) = (2 u sin(90 - prop))/(g) = (2 u cos prop)/(g)`
So, ratio of time of flight `(T_1)/(T_2) = tan prop`.